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111020111000213 is a prime number
BaseRepresentation
bin11001001111100011100010…
…010001110111001010010101
3112120002102022102100212111212
4121033203202101313022111
5104022423141404001323
61032041533534511205
732245636563121352
oct3117434221671225
9476072272325455
10111020111000213
113241340140a218
1210550536665505
1349c41c7c3a30c
141d5b58b2c5629
15cc7d4b81db78
hex64f8e2477295

111020111000213 has 2 divisors, whose sum is σ = 111020111000214. Its totient is φ = 111020111000212.

The previous prime is 111020111000177. The next prime is 111020111000269. The reversal of 111020111000213 is 312000111020111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 65753561846449 + 45266549153764 = 8108857^2 + 6728042^2 .

It is a cyclic number.

It is not a de Polignac number, because 111020111000213 - 28 = 111020110999957 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111020111020213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55510055500106 + 55510055500107.

It is an arithmetic number, because the mean of its divisors is an integer number (55510055500107).

Almost surely, 2111020111000213 is an apocalyptic number.

It is an amenable number.

111020111000213 is a deficient number, since it is larger than the sum of its proper divisors (1).

111020111000213 is an equidigital number, since it uses as much as digits as its factorization.

111020111000213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 111020111000213 its reverse (312000111020111), we get a palindrome (423020222020324).

The spelling of 111020111000213 in words is "one hundred eleven trillion, twenty billion, one hundred eleven million, two hundred thirteen", and thus it is an aban number.