111021211200113 has 2 divisors, whose sum is σ = 111021211200114. Its totient is φ = 111021211200112.

The previous prime is 111021211200089. The next prime is 111021211200121. The reversal of 111021211200113 is 311002112120111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 60881315811904 + 50139895388209 = 7802648^2 + 7080953^2 .

It is a cyclic number.

It is not a de Polignac number, because 111021211200113 - 2²² = 111021207005809 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111021211200091 and 111021211200100.

It is not a weakly prime, because it can be changed into another prime (111021211230113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55510605600056 + 55510605600057.

It is an arithmetic number, because the mean of its divisors is an integer number (55510605600057).

Almost surely, 2^{111021211200113} is an apocalyptic number.

It is an amenable number.

111021211200113 is a deficient number, since it is larger than the sum of its proper divisors (1).

111021211200113 is an equidigital number, since it uses as much as digits as its factorization.

111021211200113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 111021211200113 its reverse (311002112120111), we get a palindrome (422023323320224).

The spelling of 111021211200113 in words is "one hundred eleven trillion, twenty-one billion, two hundred eleven million, two hundred thousand, one hundred thirteen".