Base | Representation |
---|---|
bin | 1010000110001110110011… |
… | …0010011100111010000111 |
3 | 1110022100122012001000111012 |
4 | 2201203230302130322013 |
5 | 2423344220021011242 |
6 | 35340133213232435 |
7 | 2224051035102035 |
oct | 241435462347207 |
9 | 43270565030435 |
10 | 11102168141447 |
11 | 35a0448534849 |
12 | 12b381179271b |
13 | 626c1218c216 |
14 | 2a54c253d555 |
15 | 143bd5e1b282 |
hex | a18ecc9ce87 |
11102168141447 has 2 divisors, whose sum is σ = 11102168141448. Its totient is φ = 11102168141446.
The previous prime is 11102168141371. The next prime is 11102168141509. The reversal of 11102168141447 is 74414186120111.
11102168141447 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11102168141447 - 210 = 11102168140423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11102168141047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551084070723 + 5551084070724.
It is an arithmetic number, because the mean of its divisors is an integer number (5551084070724).
Almost surely, 211102168141447 is an apocalyptic number.
11102168141447 is a deficient number, since it is larger than the sum of its proper divisors (1).
11102168141447 is an equidigital number, since it uses as much as digits as its factorization.
11102168141447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43008, while the sum is 41.
The spelling of 11102168141447 in words is "eleven trillion, one hundred two billion, one hundred sixty-eight million, one hundred forty-one thousand, four hundred forty-seven".
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