Base | Representation |
---|---|
bin | 1010000110001110111010… |
… | …1100000001100101110111 |
3 | 1110022100201102000011110201 |
4 | 2201203232230001211313 |
5 | 2423344301200324002 |
6 | 35340140312301331 |
7 | 2224051603015411 |
oct | 241435654014567 |
9 | 43270642004421 |
10 | 11102200011127 |
11 | 35a0464521a25 |
12 | 12b38203a1847 |
13 | 626c1896a214 |
14 | 2a54c68779b1 |
15 | 143bd8b14087 |
hex | a18eeb01977 |
11102200011127 has 2 divisors, whose sum is σ = 11102200011128. Its totient is φ = 11102200011126.
The previous prime is 11102200011109. The next prime is 11102200011137. The reversal of 11102200011127 is 72111000220111.
11102200011127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11102200011127 - 211 = 11102200009079 is a prime.
It is a super-3 number, since 3×111022000111273 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11102200011137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551100005563 + 5551100005564.
It is an arithmetic number, because the mean of its divisors is an integer number (5551100005564).
Almost surely, 211102200011127 is an apocalyptic number.
11102200011127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11102200011127 is an equidigital number, since it uses as much as digits as its factorization.
11102200011127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 11102200011127 its reverse (72111000220111), we get a palindrome (83213200231238).
The spelling of 11102200011127 in words is "eleven trillion, one hundred two billion, two hundred million, eleven thousand, one hundred twenty-seven".
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