11102200102031 has 2 divisors, whose sum is σ = 11102200102032. Its totient is φ = 11102200102030.

The previous prime is 11102200102001. The next prime is 11102200102093. The reversal of 11102200102031 is 13020100220111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11102200102031 - 2¹⁰ = 11102200101007 is a prime.

It is a super-3 number, since 3×11102200102031³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 11102200101997 and 11102200102015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11102200102001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551100051015 + 5551100051016.

It is an arithmetic number, because the mean of its divisors is an integer number (5551100051016).

Almost surely, 2^{11102200102031} is an apocalyptic number.

11102200102031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11102200102031 is an equidigital number, since it uses as much as digits as its factorization.

11102200102031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 11102200102031 its reverse (13020100220111), we get a palindrome (24122300322142).

The spelling of 11102200102031 in words is "eleven trillion, one hundred two billion, two hundred million, one hundred two thousand, thirty-one".