Search a number
-
+
111022100130022 = 255511050065011
BaseRepresentation
bin11001001111100101011000…
…110101110010100011100110
3112120002121110001021010122021
4121033211120311302203212
5104022441230113130042
61032042503152453354
732246040065340544
oct3117453065624346
9476077401233567
10111022100130022
1132414232201954
12105509b084a25a
1349c44540799c3
141d5b6d9550d94
15cc7e16285867
hex64f958d728e6

111022100130022 has 4 divisors (see below), whose sum is σ = 166533150195036. Its totient is φ = 55511050065010.

The previous prime is 111022100129959. The next prime is 111022100130083. The reversal of 111022100130022 is 220031001220111.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 111022100129978 and 111022100130005.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27755525032504 + ... + 27755525032507.

It is an arithmetic number, because the mean of its divisors is an integer number (41633287548759).

Almost surely, 2111022100130022 is an apocalyptic number.

111022100130022 is a deficient number, since it is larger than the sum of its proper divisors (55511050065014).

111022100130022 is an equidigital number, since it uses as much as digits as its factorization.

111022100130022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55511050065013.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 111022100130022 its reverse (220031001220111), we get a palindrome (331053101350133).

The spelling of 111022100130022 in words is "one hundred eleven trillion, twenty-two billion, one hundred million, one hundred thirty thousand, twenty-two".

Divisors: 1 2 55511050065011 111022100130022