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1110221121223 is a prime number
BaseRepresentation
bin10000001001111110010…
…101011110011011000111
310221010200012220112011001
4100021332111132123013
5121142213101334343
62210010055354131
7143132212552534
oct20117625363307
93833605815131
101110221121223
11398929974715
1215b202982947
13809025365b6
143ba40b49d8b
151dd2ce8b44d
hex1027e55e6c7

1110221121223 has 2 divisors, whose sum is σ = 1110221121224. Its totient is φ = 1110221121222.

The previous prime is 1110221121197. The next prime is 1110221121239. The reversal of 1110221121223 is 3221211220111.

It is a strong prime.

It is an emirp because it is prime and its reverse (3221211220111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1110221121223 - 213 = 1110221113031 is a prime.

It is a super-2 number, since 2×11102211212232 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1110221121223.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1110221121293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555110560611 + 555110560612.

It is an arithmetic number, because the mean of its divisors is an integer number (555110560612).

Almost surely, 21110221121223 is an apocalyptic number.

1110221121223 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110221121223 is an equidigital number, since it uses as much as digits as its factorization.

1110221121223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 1110221121223 its reverse (3221211220111), we get a palindrome (4331432341334).

The spelling of 1110221121223 in words is "one trillion, one hundred ten billion, two hundred twenty-one million, one hundred twenty-one thousand, two hundred twenty-three".