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111022212001133 is a prime number
BaseRepresentation
bin11001001111100101011111…
…100000100010110101101101
3112120002121201211202202221202
4121033211133200202311231
5104022441442233014013
61032042522230335245
732246042624254436
oct3117453740426555
9476077654682852
10111022212001133
113241428a371314
1210550a221ba525
1349c44712b8924
141d5b70a35248d
15cc7e20ed2858
hex64f95f822d6d

111022212001133 has 2 divisors, whose sum is σ = 111022212001134. Its totient is φ = 111022212001132.

The previous prime is 111022212001097. The next prime is 111022212001147. The reversal of 111022212001133 is 331100212220111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91166079936649 + 19856132064484 = 9548093^2 + 4456022^2 .

It is an emirp because it is prime and its reverse (331100212220111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111022212001133 - 210 = 111022212000109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111022212001033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55511106000566 + 55511106000567.

It is an arithmetic number, because the mean of its divisors is an integer number (55511106000567).

Almost surely, 2111022212001133 is an apocalyptic number.

It is an amenable number.

111022212001133 is a deficient number, since it is larger than the sum of its proper divisors (1).

111022212001133 is an equidigital number, since it uses as much as digits as its factorization.

111022212001133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 111022212001133 its reverse (331100212220111), we get a palindrome (442122424221244).

The spelling of 111022212001133 in words is "one hundred eleven trillion, twenty-two billion, two hundred twelve million, one thousand, one hundred thirty-three".