Base | Representation |
---|---|
bin | 10000001001111110110… |
… | …111010110000110110011 |
3 | 10221010200211121121121112 |
4 | 100021332313112012303 |
5 | 121142222340000201 |
6 | 2210011013543535 |
7 | 143132351202404 |
oct | 20117667260663 |
9 | 3833624547545 |
10 | 1110230000051 |
11 | 398933989497 |
12 | 15b205944bab |
13 | 80904324a43 |
14 | 3ba41dbb9ab |
15 | 1dd2db420bb |
hex | 1027edd61b3 |
1110230000051 has 2 divisors, whose sum is σ = 1110230000052. Its totient is φ = 1110230000050.
The previous prime is 1110230000027. The next prime is 1110230000069. The reversal of 1110230000051 is 1500000320111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1110230000051 - 210 = 1110229999027 is a prime.
It is a super-2 number, since 2×11102300000512 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1110229999990 and 1110230000035.
It is not a weakly prime, because it can be changed into another prime (1110230000021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555115000025 + 555115000026.
It is an arithmetic number, because the mean of its divisors is an integer number (555115000026).
Almost surely, 21110230000051 is an apocalyptic number.
1110230000051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110230000051 is an equidigital number, since it uses as much as digits as its factorization.
1110230000051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30, while the sum is 14.
Adding to 1110230000051 its reverse (1500000320111), we get a palindrome (2610230320162).
The spelling of 1110230000051 in words is "one trillion, one hundred ten billion, two hundred thirty million, fifty-one", and thus it is an aban number.
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