Base | Representation |
---|---|
bin | 10000001001111110110… |
… | …111110110000111001111 |
3 | 10221010200211212021110002 |
4 | 100021332313312013033 |
5 | 121142222403144101 |
6 | 2210011020434515 |
7 | 143132352256541 |
oct | 20117667660717 |
9 | 3833624767402 |
10 | 1110230131151 |
11 | 398933a68a39 |
12 | 15b2059a8a3b |
13 | 8090436c60b |
14 | 3ba42013691 |
15 | 1dd2db6ad6b |
hex | 1027edf61cf |
1110230131151 has 2 divisors, whose sum is σ = 1110230131152. Its totient is φ = 1110230131150.
The previous prime is 1110230131099. The next prime is 1110230131267. The reversal of 1110230131151 is 1511310320111.
It is a weak prime.
It is an emirp because it is prime and its reverse (1511310320111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1110230131151 is a prime.
It is a super-2 number, since 2×11102301311512 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1110230131951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555115065575 + 555115065576.
It is an arithmetic number, because the mean of its divisors is an integer number (555115065576).
Almost surely, 21110230131151 is an apocalyptic number.
1110230131151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110230131151 is an equidigital number, since it uses as much as digits as its factorization.
1110230131151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 20.
Adding to 1110230131151 its reverse (1511310320111), we get a palindrome (2621540451262).
The spelling of 1110230131151 in words is "one trillion, one hundred ten billion, two hundred thirty million, one hundred thirty-one thousand, one hundred fifty-one".
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