11103210030113 has 4 divisors (see below), whose sum is σ = 11339448541440. Its totient is φ = 10866971518788.

The previous prime is 11103210030043. The next prime is 11103210030139. The reversal of 11103210030113 is 31103001230111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11103210030113 - 2⁴² = 6705163519009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11103210030091 and 11103210030100.

It is not an unprimeable number, because it can be changed into a prime (11103210030313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118119255593 + ... + 118119255686.

It is an arithmetic number, because the mean of its divisors is an integer number (2834862135360).

Almost surely, 2^{11103210030113} is an apocalyptic number.

It is an amenable number.

11103210030113 is a deficient number, since it is larger than the sum of its proper divisors (236238511327).

11103210030113 is an equidigital number, since it uses as much as digits as its factorization.

11103210030113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 236238511326.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11103210030113 its reverse (31103001230111), we get a palindrome (42206211260224).

The spelling of 11103210030113 in words is "eleven trillion, one hundred three billion, two hundred ten million, thirty thousand, one hundred thirteen".