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11103340433 = 671391192241
BaseRepresentation
bin10100101011100111…
…11000011110010001
31001122210220010122212
422111303320132101
5140214423343213
65033435041505
7542102556623
oct122563703621
931583803585
1011103340433
114788601009
12219a5a0295
13107c46a733
147748d0c13
1544eba39a8
hex295cf8791

11103340433 has 8 divisors (see below), whose sum is σ = 11350143840. Its totient is φ = 10858921920.

The previous prime is 11103340411. The next prime is 11103340447. The reversal of 11103340433 is 33404330111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11103340433 - 28 = 11103340177 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11103340399 and 11103340408.

It is not an unprimeable number, because it can be changed into a prime (11103340453) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 586808 + ... + 605433.

It is an arithmetic number, because the mean of its divisors is an integer number (1418767980).

Almost surely, 211103340433 is an apocalyptic number.

It is an amenable number.

11103340433 is a deficient number, since it is larger than the sum of its proper divisors (246803407).

11103340433 is a wasteful number, since it uses less digits than its factorization.

11103340433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1192447.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 11103340433 its reverse (33404330111), we get a palindrome (44507670544).

The spelling of 11103340433 in words is "eleven billion, one hundred three million, three hundred forty thousand, four hundred thirty-three".

Divisors: 1 67 139 9313 1192241 79880147 165721499 11103340433