Base | Representation |
---|---|
bin | 10000001010001001110… |
… | …001011100110101001101 |
3 | 10221011011120222011222121 |
4 | 100022021301130311031 |
5 | 121143111212112414 |
6 | 2210041112212541 |
7 | 143140032542053 |
oct | 20121161346515 |
9 | 3834146864877 |
10 | 1110413004109 |
11 | 398a18213112 |
12 | 15b25709a151 |
13 | 8093320b076 |
14 | 3ba5c4181d3 |
15 | 1dd3ec40724 |
hex | 10289c5cd4d |
1110413004109 has 2 divisors, whose sum is σ = 1110413004110. Its totient is φ = 1110413004108.
The previous prime is 1110413004083. The next prime is 1110413004143. The reversal of 1110413004109 is 9014003140111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1048057920009 + 62355084100 = 1023747^2 + 249710^2 .
It is an emirp because it is prime and its reverse (9014003140111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1110413004109 - 213 = 1110412995917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1110413004149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555206502054 + 555206502055.
It is an arithmetic number, because the mean of its divisors is an integer number (555206502055).
Almost surely, 21110413004109 is an apocalyptic number.
It is an amenable number.
1110413004109 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110413004109 is an equidigital number, since it uses as much as digits as its factorization.
1110413004109 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 1110413004109 in words is "one trillion, one hundred ten billion, four hundred thirteen million, four thousand, one hundred nine".
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