Base | Representation |
---|---|
bin | 1010000110010110101111… |
… | …1000110011001110000101 |
3 | 1110022120010210110200011021 |
4 | 2201211223320303032011 |
5 | 2423413101412342013 |
6 | 35341124545311141 |
7 | 2224154630000143 |
oct | 241455370631605 |
9 | 43276123420137 |
10 | 11104300512133 |
11 | 35a1342172474 |
12 | 12b41079354b1 |
13 | 627191ba211a |
14 | 2a5645814593 |
15 | 143cad229a8d |
hex | a196be33385 |
11104300512133 has 2 divisors, whose sum is σ = 11104300512134. Its totient is φ = 11104300512132.
The previous prime is 11104300512091. The next prime is 11104300512139. The reversal of 11104300512133 is 33121500340111.
11104300512133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6535830301729 + 4568470210404 = 2556527^2 + 2137398^2 .
It is an emirp because it is prime and its reverse (33121500340111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11104300512133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11104300512098 and 11104300512107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11104300512139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5552150256066 + 5552150256067.
It is an arithmetic number, because the mean of its divisors is an integer number (5552150256067).
Almost surely, 211104300512133 is an apocalyptic number.
It is an amenable number.
11104300512133 is a deficient number, since it is larger than the sum of its proper divisors (1).
11104300512133 is an equidigital number, since it uses as much as digits as its factorization.
11104300512133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 11104300512133 its reverse (33121500340111), we get a palindrome (44225800852244).
The spelling of 11104300512133 in words is "eleven trillion, one hundred four billion, three hundred million, five hundred twelve thousand, one hundred thirty-three".
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