11104314433 has 2 divisors, whose sum is σ = 11104314434. Its totient is φ = 11104314432.

The previous prime is 11104314317. The next prime is 11104314461. The reversal of 11104314433 is 33441340111.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11104312129 + 2304 = 105377^2 + 48^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11104314433 is a prime.

It is a super-2 number, since 2×11104314433² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11104314398 and 11104314407.

It is not a weakly prime, because it can be changed into another prime (11104315433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5552157216 + 5552157217.

It is an arithmetic number, because the mean of its divisors is an integer number (5552157217).

Almost surely, 2^11104314433 is an apocalyptic number.

It is an amenable number.

11104314433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11104314433 is an equidigital number, since it uses as much as digits as its factorization.

11104314433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 11104314433 its reverse (33441340111), we get a palindrome (44545654544).

The spelling of 11104314433 in words is "eleven billion, one hundred four million, three hundred fourteen thousand, four hundred thirty-three".