1110433130 has 16 divisors (see below), whose sum is σ = 2000194560. Its totient is φ = 443858832.

The previous prime is 1110433127. The next prime is 1110433147. The reversal of 1110433130 is 313340111.

It is a junction number, because it is equal to n+sod(n) for n = 1110433099 and 1110433108.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24194 + ... + 52973.

It is an arithmetic number, because the mean of its divisors is an integer number (125012160).

Almost surely, 2^1110433130 is an apocalyptic number.

1110433130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1110433130 is a deficient number, since it is larger than the sum of its proper divisors (889761430).

1110433130 is a wasteful number, since it uses less digits than its factorization.

1110433130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 78613.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 1110433130 is about 33323.1620648461. The cubic root of 1110433130 is about 1035.5334612941.

Adding to 1110433130 its reverse (313340111), we get a palindrome (1423773241).

The spelling of 1110433130 in words is "one billion, one hundred ten million, four hundred thirty-three thousand, one hundred thirty".