Base | Representation |
---|---|
bin | 1010000110010111001111… |
… | …0110110110110000001011 |
3 | 1110022120111010001201221002 |
4 | 2201211303312312300023 |
5 | 2423413340130020133 |
6 | 35341150123205215 |
7 | 2224161142333133 |
oct | 241456366666013 |
9 | 43276433051832 |
10 | 11104434220043 |
11 | 35a140069717a |
12 | 12b414467680b |
13 | 6271b37b8528 |
14 | 2a565949bac3 |
15 | 143cb9d3bce8 |
hex | a1973db6c0b |
11104434220043 has 2 divisors, whose sum is σ = 11104434220044. Its totient is φ = 11104434220042.
The previous prime is 11104434219979. The next prime is 11104434220057. The reversal of 11104434220043 is 34002243440111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11104434220043 - 26 = 11104434219979 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11104434219988 and 11104434220015.
It is not a weakly prime, because it can be changed into another prime (11104434226043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5552217110021 + 5552217110022.
It is an arithmetic number, because the mean of its divisors is an integer number (5552217110022).
Almost surely, 211104434220043 is an apocalyptic number.
11104434220043 is a deficient number, since it is larger than the sum of its proper divisors (1).
11104434220043 is an equidigital number, since it uses as much as digits as its factorization.
11104434220043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 11104434220043 its reverse (34002243440111), we get a palindrome (45106677660154).
The spelling of 11104434220043 in words is "eleven trillion, one hundred four billion, four hundred thirty-four million, two hundred twenty thousand, forty-three".
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