Base | Representation |
---|---|
bin | 1010000110011101100001… |
… | …1100001101101000101111 |
3 | 1110022201211201102100212001 |
4 | 2201213120130031220233 |
5 | 2423430314131002303 |
6 | 35342025404353131 |
7 | 2224251023065012 |
oct | 241473034155057 |
9 | 43281751370761 |
10 | 11106121734703 |
11 | 35a2097201996 |
12 | 12b45358457a7 |
13 | 6273c22b2c08 |
14 | 2a5779653379 |
15 | 143d6807631d |
hex | a19d870da2f |
11106121734703 has 2 divisors, whose sum is σ = 11106121734704. Its totient is φ = 11106121734702.
The previous prime is 11106121734641. The next prime is 11106121734779. The reversal of 11106121734703 is 30743712160111.
11106121734703 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11106121734703 - 217 = 11106121603631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11106121734203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5553060867351 + 5553060867352.
It is an arithmetic number, because the mean of its divisors is an integer number (5553060867352).
Almost surely, 211106121734703 is an apocalyptic number.
11106121734703 is a deficient number, since it is larger than the sum of its proper divisors (1).
11106121734703 is an equidigital number, since it uses as much as digits as its factorization.
11106121734703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21168, while the sum is 37.
Adding to 11106121734703 its reverse (30743712160111), we get a palindrome (41849833894814).
The spelling of 11106121734703 in words is "eleven trillion, one hundred six billion, one hundred twenty-one million, seven hundred thirty-four thousand, seven hundred three".
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