Base | Representation |
---|---|
bin | 11001010000101101111100… |
… | …101100001011010001010111 |
3 | 112120101001112210022110021021 |
4 | 121100231330230023101113 |
5 | 104030230310304012134 |
6 | 1032142350201102011 |
7 | 32254465561663003 |
oct | 3120557454132127 |
9 | 476331483273237 |
10 | 111100011000919 |
11 | 32444282925356 |
12 | 10563b14a87907 |
13 | 49cb8bc42ba45 |
14 | 1d613aaa6d703 |
15 | cc9e761380b4 |
hex | 650b7cb0b457 |
111100011000919 has 2 divisors, whose sum is σ = 111100011000920. Its totient is φ = 111100011000918.
The previous prime is 111100011000899. The next prime is 111100011000977. The reversal of 111100011000919 is 919000110001111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111100011000919 - 25 = 111100011000887 is a prime.
It is a super-2 number, since 2×1111000110009192 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 111100011000893 and 111100011000902.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111100011000119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55550005500459 + 55550005500460.
It is an arithmetic number, because the mean of its divisors is an integer number (55550005500460).
Almost surely, 2111100011000919 is an apocalyptic number.
111100011000919 is a deficient number, since it is larger than the sum of its proper divisors (1).
111100011000919 is an equidigital number, since it uses as much as digits as its factorization.
111100011000919 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 25.
The spelling of 111100011000919 in words is "one hundred eleven trillion, one hundred billion, eleven million, nine hundred nineteen", and thus it is an aban number.
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