11110001114053 has 2 divisors, whose sum is σ = 11110001114054. Its totient is φ = 11110001114052.

The previous prime is 11110001114011. The next prime is 11110001114063. The reversal of 11110001114053 is 35041110001111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9528963957604 + 1581037156449 = 3086902^2 + 1257393^2 .

It is a cyclic number.

It is not a de Polignac number, because 11110001114053 - 2²¹ = 11109999016901 is a prime.

It is a super-2 number, since 2×11110001114053² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11110001114053.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11110001114063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555000557026 + 5555000557027.

It is an arithmetic number, because the mean of its divisors is an integer number (5555000557027).

Almost surely, 2^{11110001114053} is an apocalyptic number.

It is an amenable number.

11110001114053 is a deficient number, since it is larger than the sum of its proper divisors (1).

11110001114053 is an equidigital number, since it uses as much as digits as its factorization.

11110001114053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 19.

Adding to 11110001114053 its reverse (35041110001111), we get a palindrome (46151111115164).

The spelling of 11110001114053 in words is "eleven trillion, one hundred ten billion, one million, one hundred fourteen thousand, fifty-three".