111100130113 has 4 divisors (see below), whose sum is σ = 126971577280. Its totient is φ = 95228682948.

The previous prime is 111100130077. The next prime is 111100130117. The reversal of 111100130113 is 311031001111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 111100130113 - 2⁹ = 111100129601 is a prime.

It is a super-2 number, since 2×111100130113² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111100130093 and 111100130102.

It is not an unprimeable number, because it can be changed into a prime (111100130117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7935723573 + ... + 7935723586.

It is an arithmetic number, because the mean of its divisors is an integer number (31742894320).

Almost surely, 2^111100130113 is an apocalyptic number.

It is an amenable number.

111100130113 is a deficient number, since it is larger than the sum of its proper divisors (15871447167).

111100130113 is an equidigital number, since it uses as much as digits as its factorization.

111100130113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15871447166.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 111100130113 its reverse (311031001111), we get a palindrome (422131131224).

The spelling of 111100130113 in words is "one hundred eleven billion, one hundred million, one hundred thirty thousand, one hundred thirteen".