Base | Representation |
---|---|
bin | 1010000110101100000011… |
… | …1010111101110100000111 |
3 | 1110100002220112122222112211 |
4 | 2201223000322331310013 |
5 | 2424011311130013341 |
6 | 35343512415124251 |
7 | 2224446463532644 |
oct | 241530072756407 |
9 | 43302815588484 |
10 | 11110022110471 |
11 | 35a3808930a39 |
12 | 12b5243b13687 |
13 | 627894392b7b |
14 | 2a5a29672dcb |
15 | 143ee56bd181 |
hex | a1ac0ebdd07 |
11110022110471 has 2 divisors, whose sum is σ = 11110022110472. Its totient is φ = 11110022110470.
The previous prime is 11110022110457. The next prime is 11110022110489. The reversal of 11110022110471 is 17401122001111.
11110022110471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11110022110471 - 221 = 11110020013319 is a prime.
It is a super-3 number, since 3×111100221104713 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11110022150471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555011055235 + 5555011055236.
It is an arithmetic number, because the mean of its divisors is an integer number (5555011055236).
Almost surely, 211110022110471 is an apocalyptic number.
11110022110471 is a deficient number, since it is larger than the sum of its proper divisors (1).
11110022110471 is an equidigital number, since it uses as much as digits as its factorization.
11110022110471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 11110022110471 its reverse (17401122001111), we get a palindrome (28511144111582).
The spelling of 11110022110471 in words is "eleven trillion, one hundred ten billion, twenty-two million, one hundred ten thousand, four hundred seventy-one".
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