1111009999963 has 2 divisors, whose sum is σ = 1111009999964. Its totient is φ = 1111009999962.

The previous prime is 1111009999949. The next prime is 1111010000057. The reversal of 1111009999963 is 3699999001111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1111009999963 - 2³⁷ = 973571046491 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1111009999898 and 1111009999907.

It is not a weakly prime, because it can be changed into another prime (1111009999903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555504999981 + 555504999982.

It is an arithmetic number, because the mean of its divisors is an integer number (555504999982).

Almost surely, 2^{1111009999963} is an apocalyptic number.

1111009999963 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111009999963 is an equidigital number, since it uses as much as digits as its factorization.

1111009999963 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1062882, while the sum is 58.

The spelling of 1111009999963 in words is "one trillion, one hundred eleven billion, nine million, nine hundred ninety-nine thousand, nine hundred sixty-three".