Base | Representation |
---|---|
bin | 10000001010101101010… |
… | …110110011110010111001 |
3 | 10221012201012022201110122 |
4 | 100022231112303302321 |
5 | 121200322030000212 |
6 | 2210220240023025 |
7 | 143160602120036 |
oct | 20125526636271 |
9 | 3835635281418 |
10 | 1111010000057 |
11 | 3991a41a9aa1 |
12 | 15b3a3001a75 |
13 | 809c9ac44c9 |
14 | 3bab781c38d |
15 | 1dd77368272 |
hex | 102ad5b3cb9 |
1111010000057 has 2 divisors, whose sum is σ = 1111010000058. Its totient is φ = 1111010000056.
The previous prime is 1111009999963. The next prime is 1111010000059. The reversal of 1111010000057 is 7500000101111.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1086641541241 + 24368458816 = 1042421^2 + 156104^2 .
It is a cyclic number.
It is not a de Polignac number, because 1111010000057 - 234 = 1093830130873 is a prime.
Together with 1111010000059, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1111010000059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555505000028 + 555505000029.
It is an arithmetic number, because the mean of its divisors is an integer number (555505000029).
Almost surely, 21111010000057 is an apocalyptic number.
It is an amenable number.
1111010000057 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111010000057 is an equidigital number, since it uses as much as digits as its factorization.
1111010000057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 35, while the sum is 17.
Adding to 1111010000057 its reverse (7500000101111), we get a palindrome (8611010101168).
The spelling of 1111010000057 in words is "one trillion, one hundred eleven billion, ten million, fifty-seven", and thus it is an aban number.
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