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1111010000131 is a prime number
BaseRepresentation
bin10000001010101101010…
…110110011110100000011
310221012201012022201120101
4100022231112303310003
5121200322030001011
62210220240023231
7143160602120203
oct20125526636403
93835635281511
101111010000131
113991a41aa059
1215b3a3001b17
13809c9ac4555
143bab781c403
151dd773682c1
hex102ad5b3d03

1111010000131 has 2 divisors, whose sum is σ = 1111010000132. Its totient is φ = 1111010000130.

The previous prime is 1111010000129. The next prime is 1111010000159. The reversal of 1111010000131 is 1310000101111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1111010000131 - 21 = 1111010000129 is a prime.

It is a super-2 number, since 2×11110100001312 (a number of 25 digits) contains 22 as substring.

Together with 1111010000129, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1111010000231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555505000065 + 555505000066.

It is an arithmetic number, because the mean of its divisors is an integer number (555505000066).

Almost surely, 21111010000131 is an apocalyptic number.

1111010000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111010000131 is an equidigital number, since it uses as much as digits as its factorization.

1111010000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 10.

Adding to 1111010000131 its reverse (1310000101111), we get a palindrome (2421010101242).

The spelling of 1111010000131 in words is "one trillion, one hundred eleven billion, ten million, one hundred thirty-one", and thus it is an aban number.