Base | Representation |
---|---|
bin | 110011101111000110… |
… | …0111011000100011111 |
3 | 101121202220020001212012 |
4 | 1213132030323010133 |
5 | 3310014120041111 |
6 | 123012315501435 |
7 | 11012133241031 |
oct | 1473614730437 |
9 | 347686201765 |
10 | 111102112031 |
11 | 431332781a9 |
12 | 19647a5787b |
13 | a627939cc1 |
14 | 553d711c51 |
15 | 2d53c4948b |
hex | 19de33b11f |
111102112031 has 2 divisors, whose sum is σ = 111102112032. Its totient is φ = 111102112030.
The previous prime is 111102111997. The next prime is 111102112061. The reversal of 111102112031 is 130211201111.
It is a strong prime.
It is an emirp because it is prime and its reverse (130211201111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111102112031 - 210 = 111102111007 is a prime.
It is a super-2 number, since 2×1111021120312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 111102111997 and 111102112015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111102112061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55551056015 + 55551056016.
It is an arithmetic number, because the mean of its divisors is an integer number (55551056016).
Almost surely, 2111102112031 is an apocalyptic number.
111102112031 is a deficient number, since it is larger than the sum of its proper divisors (1).
111102112031 is an equidigital number, since it uses as much as digits as its factorization.
111102112031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 111102112031 its reverse (130211201111), we get a palindrome (241313313142).
The spelling of 111102112031 in words is "one hundred eleven billion, one hundred two million, one hundred twelve thousand, thirty-one".
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