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11110222000993 is a prime number
BaseRepresentation
bin1010000110101100110011…
…0101011111001101100001
31110100010102110210110210111
42201223030311133031201
52424012213313012433
635343544315331321
72224454441553103
oct241531465371541
943303373713714
1011110222000993
1135a3900749715
1212b529aa50b41
136278c690c39b
142a5a48027573
15144008004dcd
hexa1accd5f361

11110222000993 has 2 divisors, whose sum is σ = 11110222000994. Its totient is φ = 11110222000992.

The previous prime is 11110222000987. The next prime is 11110222001041. The reversal of 11110222000993 is 39900022201111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6936017511424 + 4174204489569 = 2633632^2 + 2043087^2 .

It is a cyclic number.

It is not a de Polignac number, because 11110222000993 - 221 = 11110219903841 is a prime.

It is a super-2 number, since 2×111102220009932 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11110222000393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555111000496 + 5555111000497.

It is an arithmetic number, because the mean of its divisors is an integer number (5555111000497).

Almost surely, 211110222000993 is an apocalyptic number.

It is an amenable number.

11110222000993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11110222000993 is an equidigital number, since it uses as much as digits as its factorization.

11110222000993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 31.

The spelling of 11110222000993 in words is "eleven trillion, one hundred ten billion, two hundred twenty-two million, nine hundred ninety-three", and thus it is an aban number.