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111102644399941 is a prime number
BaseRepresentation
bin11001010000110000011001…
…101001110010111101000101
3112120101022100022111222121101
4121100300121221302331011
5104030301203431244231
61032143503352020101
732254621046340115
oct3120603151627505
9476338308458541
10111102644399941
1132445404361a87
121056452a991631
1349cbc1bb96b0c
141d6157a6c7045
15cca07c414661
hex650c19a72f45

111102644399941 has 2 divisors, whose sum is σ = 111102644399942. Its totient is φ = 111102644399940.

The previous prime is 111102644399933. The next prime is 111102644400049. The reversal of 111102644399941 is 149993446201111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 69033747909025 + 42068896490916 = 8308655^2 + 6486054^2 .

It is a cyclic number.

It is not a de Polignac number, because 111102644399941 - 23 = 111102644399933 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111102644399921) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55551322199970 + 55551322199971.

It is an arithmetic number, because the mean of its divisors is an integer number (55551322199971).

Almost surely, 2111102644399941 is an apocalyptic number.

It is an amenable number.

111102644399941 is a deficient number, since it is larger than the sum of its proper divisors (1).

111102644399941 is an equidigital number, since it uses as much as digits as its factorization.

111102644399941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1679616, while the sum is 55.

The spelling of 111102644399941 in words is "one hundred eleven trillion, one hundred two billion, six hundred forty-four million, three hundred ninety-nine thousand, nine hundred forty-one".