111104010141 has 4 divisors (see below), whose sum is σ = 148138680192. Its totient is φ = 74069340092.

The previous prime is 111104010109. The next prime is 111104010161. The reversal of 111104010141 is 141010401111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 141010401111 = 3 ⋅47003467037.

It is a cyclic number.

It is not a de Polignac number, because 111104010141 - 2⁵ = 111104010109 is a prime.

It is a super-2 number, since 2×111104010141² (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 111104010141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111104010161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18517335021 + ... + 18517335026.

It is an arithmetic number, because the mean of its divisors is an integer number (37034670048).

Almost surely, 2^111104010141 is an apocalyptic number.

It is an amenable number.

111104010141 is a deficient number, since it is larger than the sum of its proper divisors (37034670051).

111104010141 is an equidigital number, since it uses as much as digits as its factorization.

111104010141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37034670050.

The product of its (nonzero) digits is 16, while the sum is 15.

Adding to 111104010141 its reverse (141010401111), we get a palindrome (252114411252).

The spelling of 111104010141 in words is "one hundred eleven billion, one hundred four million, ten thousand, one hundred forty-one".