Base | Representation |
---|---|
bin | 1010000110101101111000… |
… | …1100001001010001100011 |
3 | 1110100011011202122112102201 |
4 | 2201223132030021101203 |
5 | 2424013312331344443 |
6 | 35344033235554031 |
7 | 2224464605402116 |
oct | 241533614112143 |
9 | 43304152575381 |
10 | 11110513153123 |
11 | 35a3a4002a60a |
12 | 12b536045b917 |
13 | 62794202cb57 |
14 | 2a5a7497657d |
15 | 14402386734d |
hex | a1ade309463 |
11110513153123 has 2 divisors, whose sum is σ = 11110513153124. Its totient is φ = 11110513153122.
The previous prime is 11110513153121. The next prime is 11110513153183. The reversal of 11110513153123 is 32135131501111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11110513153123 - 21 = 11110513153121 is a prime.
Together with 11110513153121, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 11110513153091 and 11110513153100.
It is not a weakly prime, because it can be changed into another prime (11110513153121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555256576561 + 5555256576562.
It is an arithmetic number, because the mean of its divisors is an integer number (5555256576562).
Almost surely, 211110513153123 is an apocalyptic number.
11110513153123 is a deficient number, since it is larger than the sum of its proper divisors (1).
11110513153123 is an equidigital number, since it uses as much as digits as its factorization.
11110513153123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1350, while the sum is 28.
Adding to 11110513153123 its reverse (32135131501111), we get a palindrome (43245644654234).
The spelling of 11110513153123 in words is "eleven trillion, one hundred ten billion, five hundred thirteen million, one hundred fifty-three thousand, one hundred twenty-three".
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