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11111000012113 is a prime number
BaseRepresentation
bin1010000110101111101100…
…1101010111010101010001
31110100012102200202112102011
42201223323031113111101
52424020312000341423
635344153431022521
72224512636545101
oct241537315272521
943305380675364
1011111000012113
1135a416a930a11
1212b547750aa41
136279bbb637b1
142a5abd4ab201
15144051486b0d
hexa1afb357551

11111000012113 has 2 divisors, whose sum is σ = 11111000012114. Its totient is φ = 11111000012112.

The previous prime is 11111000012089. The next prime is 11111000012141. The reversal of 11111000012113 is 31121000011111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8642230014289 + 2468769997824 = 2939767^2 + 1571232^2 .

It is a cyclic number.

It is not a de Polignac number, because 11111000012113 - 229 = 11110463141201 is a prime.

It is a super-2 number, since 2×111110000121132 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11111000012093 and 11111000012102.

It is not a weakly prime, because it can be changed into another prime (11111000012183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555500006056 + 5555500006057.

It is an arithmetic number, because the mean of its divisors is an integer number (5555500006057).

Almost surely, 211111000012113 is an apocalyptic number.

It is an amenable number.

11111000012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111000012113 is an equidigital number, since it uses as much as digits as its factorization.

11111000012113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 11111000012113 its reverse (31121000011111), we get a palindrome (42232000023224).

The spelling of 11111000012113 in words is "eleven trillion, one hundred eleven billion, twelve thousand, one hundred thirteen".