Base | Representation |
---|---|
bin | 1010000110101111101101… |
… | …0001000000110010010111 |
3 | 1110100012102202120010010002 |
4 | 2201223323101000302113 |
5 | 2424020312221441333 |
6 | 35344153503321515 |
7 | 2224512650636663 |
oct | 241537321006227 |
9 | 43305382503102 |
10 | 11111000968343 |
11 | 35a4170424391 |
12 | 12b54778b029b |
13 | 6279bc109b03 |
14 | 2a5abd6798a3 |
15 | 1440515c50e8 |
hex | a1afb440c97 |
11111000968343 has 2 divisors, whose sum is σ = 11111000968344. Its totient is φ = 11111000968342.
The previous prime is 11111000968339. The next prime is 11111000968429. The reversal of 11111000968343 is 34386900011111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11111000968343 - 22 = 11111000968339 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11111000968297 and 11111000968306.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11111000968303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555500484171 + 5555500484172.
It is an arithmetic number, because the mean of its divisors is an integer number (5555500484172).
Almost surely, 211111000968343 is an apocalyptic number.
11111000968343 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111000968343 is an equidigital number, since it uses as much as digits as its factorization.
11111000968343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 38.
Adding to 11111000968343 its reverse (34386900011111), we get a palindrome (45497900979454).
The spelling of 11111000968343 in words is "eleven trillion, one hundred eleven billion, nine hundred sixty-eight thousand, three hundred forty-three".
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