Base | Representation |
---|---|
bin | 1010000110101111101101… |
… | …0001001011000010011011 |
3 | 1110100012102202122020201012 |
4 | 2201223323101023002123 |
5 | 2424020312224312311 |
6 | 35344153504244135 |
7 | 2224512651203255 |
oct | 241537321130233 |
9 | 43305382566635 |
10 | 11111001010331 |
11 | 35a4170452992 |
12 | 12b547791064b |
13 | 6279bc122c61 |
14 | 2a5abd68acd5 |
15 | 1440515d278b |
hex | a1afb44b09b |
11111001010331 has 2 divisors, whose sum is σ = 11111001010332. Its totient is φ = 11111001010330.
The previous prime is 11111001010231. The next prime is 11111001010339. The reversal of 11111001010331 is 13301010011111.
11111001010331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11111001010331 - 214 = 11111000993947 is a prime.
It is a super-2 number, since 2×111110010103312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11111001010339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555500505165 + 5555500505166.
It is an arithmetic number, because the mean of its divisors is an integer number (5555500505166).
Almost surely, 211111001010331 is an apocalyptic number.
11111001010331 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111001010331 is an equidigital number, since it uses as much as digits as its factorization.
11111001010331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9, while the sum is 14.
Adding to 11111001010331 its reverse (13301010011111), we get a palindrome (24412011021442).
The spelling of 11111001010331 in words is "eleven trillion, one hundred eleven billion, one million, ten thousand, three hundred thirty-one".
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