Base | Representation |
---|---|
bin | 1010000110101111101101… |
… | …0001001011000000110111 |
3 | 1110100012102202122020120111 |
4 | 2201223323101023000313 |
5 | 2424020312224311411 |
6 | 35344153504243451 |
7 | 2224512651203053 |
oct | 241537321130067 |
9 | 43305382566514 |
10 | 11111001010231 |
11 | 35a4170452901 |
12 | 12b5477910587 |
13 | 6279bc122bb5 |
14 | 2a5abd68ac63 |
15 | 1440515d2721 |
hex | a1afb44b037 |
11111001010231 has 2 divisors, whose sum is σ = 11111001010232. Its totient is φ = 11111001010230.
The previous prime is 11111001010183. The next prime is 11111001010331. The reversal of 11111001010231 is 13201010011111.
11111001010231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11111001010231 is a prime.
It is a super-2 number, since 2×111110010102312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11111001010331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555500505115 + 5555500505116.
It is an arithmetic number, because the mean of its divisors is an integer number (5555500505116).
Almost surely, 211111001010231 is an apocalyptic number.
11111001010231 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111001010231 is an equidigital number, since it uses as much as digits as its factorization.
11111001010231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 13.
Adding to 11111001010231 its reverse (13201010011111), we get a palindrome (24312011021342).
The spelling of 11111001010231 in words is "eleven trillion, one hundred eleven billion, one million, ten thousand, two hundred thirty-one".
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