Base | Representation |
---|---|
bin | 11001010000110111010110… |
… | …110000110110101000000011 |
3 | 112120102000121202100000111102 |
4 | 121100313112300312220003 |
5 | 104030412002200023412 |
6 | 1032151140355005015 |
7 | 32255304105002564 |
oct | 3120672660665003 |
9 | 476360552300442 |
10 | 111110112111107 |
11 | 324485967199aa |
12 | 10565a7389976b |
13 | 49cc83c05b115 |
14 | 1d61a883d216b |
15 | cca367d198c2 |
hex | 650dd6c36a03 |
111110112111107 has 2 divisors, whose sum is σ = 111110112111108. Its totient is φ = 111110112111106.
The previous prime is 111110112111091. The next prime is 111110112111127. The reversal of 111110112111107 is 701111211011111.
It is an a-pointer prime, because the next prime (111110112111127) can be obtained adding 111110112111107 to its sum of digits (20).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111110112111107 - 24 = 111110112111091 is a prime.
It is not a weakly prime, because it can be changed into another prime (111110112111127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555056055553 + 55555056055554.
It is an arithmetic number, because the mean of its divisors is an integer number (55555056055554).
Almost surely, 2111110112111107 is an apocalyptic number.
111110112111107 is a deficient number, since it is larger than the sum of its proper divisors (1).
111110112111107 is an equidigital number, since it uses as much as digits as its factorization.
111110112111107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14, while the sum is 20.
Adding to 111110112111107 its reverse (701111211011111), we get a palindrome (812221323122218).
The spelling of 111110112111107 in words is "one hundred eleven trillion, one hundred ten billion, one hundred twelve million, one hundred eleven thousand, one hundred seven".
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