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111110121113 = 234830874831
BaseRepresentation
bin110011101111010101…
…1011110011010011001
3101121210110021222020212
41213132223132122121
53310023142333423
6123013203300505
711012261306105
oct1473653363231
9347713258225
10111110121113
1143137848582
121964a67a735
13a6294b25c4
1455407d8905
152d547cc578
hex19deade699

111110121113 has 4 divisors (see below), whose sum is σ = 115940995968. Its totient is φ = 106279246260.

The previous prime is 111110121019. The next prime is 111110121149. The reversal of 111110121113 is 311121011111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111110121113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111110121163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2415437393 + ... + 2415437438.

It is an arithmetic number, because the mean of its divisors is an integer number (28985248992).

Almost surely, 2111110121113 is an apocalyptic number.

It is an amenable number.

111110121113 is a deficient number, since it is larger than the sum of its proper divisors (4830874855).

111110121113 is an equidigital number, since it uses as much as digits as its factorization.

111110121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4830874854.

The product of its (nonzero) digits is 6, while the sum is 14.

Adding to 111110121113 its reverse (311121011111), we get a palindrome (422231132224).

The spelling of 111110121113 in words is "one hundred eleven billion, one hundred ten million, one hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 23 4830874831 111110121113