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111110131283 is a prime number
BaseRepresentation
bin110011101111010101…
…1100000111001010011
3101121210110022111012112
41213132223200321103
53310023143200113
6123013203415535
711012261350544
oct1473653407123
9347713274175
10111110131283
1143137855188
121964a6845ab
13a6294b7118
1455407dc4cb
152d547d05a8
hex19deae0e53

111110131283 has 2 divisors, whose sum is σ = 111110131284. Its totient is φ = 111110131282.

The previous prime is 111110131267. The next prime is 111110131291. The reversal of 111110131283 is 382131011111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111110131283 - 24 = 111110131267 is a prime.

It is a super-2 number, since 2×1111101312832 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (111110131183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555065641 + 55555065642.

It is an arithmetic number, because the mean of its divisors is an integer number (55555065642).

Almost surely, 2111110131283 is an apocalyptic number.

111110131283 is a deficient number, since it is larger than the sum of its proper divisors (1).

111110131283 is an equidigital number, since it uses as much as digits as its factorization.

111110131283 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 23.

Adding to 111110131283 its reverse (382131011111), we get a palindrome (493241142394).

The spelling of 111110131283 in words is "one hundred eleven billion, one hundred ten million, one hundred thirty-one thousand, two hundred eighty-three".