Base | Representation |
---|---|
bin | 11001010000110111011100… |
… | …101010001000010111110011 |
3 | 112120102000212122102201010112 |
4 | 121100313130222020113303 |
5 | 104030412203004341313 |
6 | 1032151154250451535 |
7 | 32255306415436613 |
oct | 3120673452102763 |
9 | 476360778381115 |
10 | 111110211012083 |
11 | 3244863752a748 |
12 | 10565aa0a33bab |
13 | 49cc8566a85ca |
14 | 1d61a975b8a43 |
15 | cca3718538a8 |
hex | 650ddca885f3 |
111110211012083 has 2 divisors, whose sum is σ = 111110211012084. Its totient is φ = 111110211012082.
The previous prime is 111110211012013. The next prime is 111110211012127. The reversal of 111110211012083 is 380210112011111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111110211012083 - 214 = 111110210995699 is a prime.
It is a super-2 number, since 2×1111102110120832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (111110211012013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555105506041 + 55555105506042.
It is an arithmetic number, because the mean of its divisors is an integer number (55555105506042).
Almost surely, 2111110211012083 is an apocalyptic number.
111110211012083 is a deficient number, since it is larger than the sum of its proper divisors (1).
111110211012083 is an equidigital number, since it uses as much as digits as its factorization.
111110211012083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 23.
Adding to 111110211012083 its reverse (380210112011111), we get a palindrome (491320323023194).
The spelling of 111110211012083 in words is "one hundred eleven trillion, one hundred ten billion, two hundred eleven million, twelve thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.201 sec. • engine limits •