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11111044313209 = 23483088883183
BaseRepresentation
bin1010000110101111110111…
…0110010111000001111001
31110100012112210010021002111
42201223331312113001321
52424020404321010314
635344202052332321
72224514015235601
oct241537566270171
943305483107074
1011111044313209
1135a4192939a95
1212b548a3140a1
136279c80a4c69
142a5ac531dc01
151440552d7ec4
hexa1afdd97079

11111044313209 has 4 divisors (see below), whose sum is σ = 11594133196416. Its totient is φ = 10627955430004.

The previous prime is 11111044313203. The next prime is 11111044313219. The reversal of 11111044313209 is 90231344011111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11111044313209 - 213 = 11111044305017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11111044313203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 241544441569 + ... + 241544441614.

It is an arithmetic number, because the mean of its divisors is an integer number (2898533299104).

Almost surely, 211111044313209 is an apocalyptic number.

It is an amenable number.

11111044313209 is a deficient number, since it is larger than the sum of its proper divisors (483088883207).

11111044313209 is an equidigital number, since it uses as much as digits as its factorization.

11111044313209 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 483088883206.

The product of its (nonzero) digits is 2592, while the sum is 31.

The spelling of 11111044313209 in words is "eleven trillion, one hundred eleven billion, forty-four million, three hundred thirteen thousand, two hundred nine".

Divisors: 1 23 483088883183 11111044313209