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1111104431341 is a prime number
BaseRepresentation
bin10000001010110010111…
…111000010010011101101
310221012221210000022211121
4100022302333002103231
5121201020213300331
62210233452020541
7143163126556642
oct20126277022355
93835853008747
101111104431341
11399242537683
1215b40a761751
1380a135383c8
143bac619ddc9
151dd807bcc11
hex102b2fc24ed

1111104431341 has 2 divisors, whose sum is σ = 1111104431342. Its totient is φ = 1111104431340.

The previous prime is 1111104431287. The next prime is 1111104431351. The reversal of 1111104431341 is 1431344011111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1108764774441 + 2339656900 = 1052979^2 + 48370^2 .

It is a cyclic number.

It is not a de Polignac number, because 1111104431341 - 233 = 1102514496749 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111104431351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555552215670 + 555552215671.

It is an arithmetic number, because the mean of its divisors is an integer number (555552215671).

Almost surely, 21111104431341 is an apocalyptic number.

It is an amenable number.

1111104431341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111104431341 is an equidigital number, since it uses as much as digits as its factorization.

1111104431341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 1111104431341 its reverse (1431344011111), we get a palindrome (2542448442452).

The spelling of 1111104431341 in words is "one trillion, one hundred eleven billion, one hundred four million, four hundred thirty-one thousand, three hundred forty-one".