Base | Representation |
---|---|
bin | 10000001010110010111… |
… | …111000010010011101101 |
3 | 10221012221210000022211121 |
4 | 100022302333002103231 |
5 | 121201020213300331 |
6 | 2210233452020541 |
7 | 143163126556642 |
oct | 20126277022355 |
9 | 3835853008747 |
10 | 1111104431341 |
11 | 399242537683 |
12 | 15b40a761751 |
13 | 80a135383c8 |
14 | 3bac619ddc9 |
15 | 1dd807bcc11 |
hex | 102b2fc24ed |
1111104431341 has 2 divisors, whose sum is σ = 1111104431342. Its totient is φ = 1111104431340.
The previous prime is 1111104431287. The next prime is 1111104431351. The reversal of 1111104431341 is 1431344011111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1108764774441 + 2339656900 = 1052979^2 + 48370^2 .
It is a cyclic number.
It is not a de Polignac number, because 1111104431341 - 233 = 1102514496749 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1111104431351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555552215670 + 555552215671.
It is an arithmetic number, because the mean of its divisors is an integer number (555552215671).
Almost surely, 21111104431341 is an apocalyptic number.
It is an amenable number.
1111104431341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111104431341 is an equidigital number, since it uses as much as digits as its factorization.
1111104431341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 1111104431341 its reverse (1431344011111), we get a palindrome (2542448442452).
The spelling of 1111104431341 in words is "one trillion, one hundred eleven billion, one hundred four million, four hundred thirty-one thousand, three hundred forty-one".
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