11111125132111 has 2 divisors, whose sum is σ = 11111125132112. Its totient is φ = 11111125132110.

The previous prime is 11111125132099. The next prime is 11111125132171. The reversal of 11111125132111 is 11123152111111.

It is a m-pointer prime, because the next prime (11111125132171) can be obtained adding 11111125132111 to its product of digits (60).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11111125132111 - 2²¹ = 11111123034959 is a prime.

It is a super-4 number, since 4×11111125132111⁴ (a number of 53 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11111125132171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555562566055 + 5555562566056.

It is an arithmetic number, because the mean of its divisors is an integer number (5555562566056).

Almost surely, 2^{11111125132111} is an apocalyptic number.

11111125132111 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111125132111 is an equidigital number, since it uses as much as digits as its factorization.

11111125132111 is an evil number, because the sum of its binary digits is even.

The product of its digits is 60, while the sum is 22.

Adding to 11111125132111 its reverse (11123152111111), we get a palindrome (22234277243222).

The spelling of 11111125132111 in words is "eleven trillion, one hundred eleven billion, one hundred twenty-five million, one hundred thirty-two thousand, one hundred eleven".