111112010219993 has 2 divisors, whose sum is σ = 111112010219994. Its totient is φ = 111112010219992.

The previous prime is 111112010219953. The next prime is 111112010220053. The reversal of 111112010219993 is 399912010211111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97645069928704 + 13466940291289 = 9881552^2 + 3669733^2 .

It is a cyclic number.

It is not a de Polignac number, because 111112010219993 - 2¹⁸ = 111112009957849 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 111112010219993.

It is not a weakly prime, because it can be changed into another prime (111112010219923) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556005109996 + 55556005109997.

It is an arithmetic number, because the mean of its divisors is an integer number (55556005109997).

Almost surely, 2^{111112010219993} is an apocalyptic number.

It is an amenable number.

111112010219993 is a deficient number, since it is larger than the sum of its proper divisors (1).

111112010219993 is an equidigital number, since it uses as much as digits as its factorization.

111112010219993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8748, while the sum is 41.

The spelling of 111112010219993 in words is "one hundred eleven trillion, one hundred twelve billion, ten million, two hundred nineteen thousand, nine hundred ninety-three".