1111120310147 has 2 divisors, whose sum is σ = 1111120310148. Its totient is φ = 1111120310146.

The previous prime is 1111120310033. The next prime is 1111120310171. The reversal of 1111120310147 is 7410130211111.

It is a strong prime.

It is an emirp because it is prime and its reverse (7410130211111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1111120310147 - 2²⁶ = 1111053201283 is a prime.

It is a super-4 number, since 4×1111120310147⁴ (a number of 49 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (1111120310197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555560155073 + 555560155074.

It is an arithmetic number, because the mean of its divisors is an integer number (555560155074).

Almost surely, 2^{1111120310147} is an apocalyptic number.

1111120310147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111120310147 is an equidigital number, since it uses as much as digits as its factorization.

1111120310147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 23.

Adding to 1111120310147 its reverse (7410130211111), we get a palindrome (8521250521258).

The spelling of 1111120310147 in words is "one trillion, one hundred eleven billion, one hundred twenty million, three hundred ten thousand, one hundred forty-seven".