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111112032213157 is a prime number
BaseRepresentation
bin11001010000111001001001…
…001101011101100010100101
3112120102012120120100022100011
4121100321021031131202211
5104030424420221310112
61032152055105250221
732255402511415003
oct3120711115354245
9476365516308304
10111112032213157
1132449391554aa8
121056630a933971
1349cca86aac691
141d61bcb40da73
15cca42b698aa7
hex650e4935d8a5

111112032213157 has 2 divisors, whose sum is σ = 111112032213158. Its totient is φ = 111112032213156.

The previous prime is 111112032213109. The next prime is 111112032213197. The reversal of 111112032213157 is 751312230211111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89372557134436 + 21739475078721 = 9453706^2 + 4662561^2 .

It is a cyclic number.

It is not a de Polignac number, because 111112032213157 - 27 = 111112032213029 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111112032213197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556016106578 + 55556016106579.

It is an arithmetic number, because the mean of its divisors is an integer number (55556016106579).

Almost surely, 2111112032213157 is an apocalyptic number.

It is an amenable number.

111112032213157 is a deficient number, since it is larger than the sum of its proper divisors (1).

111112032213157 is an equidigital number, since it uses as much as digits as its factorization.

111112032213157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2520, while the sum is 31.

Adding to 111112032213157 its reverse (751312230211111), we get a palindrome (862424262424268).

The spelling of 111112032213157 in words is "one hundred eleven trillion, one hundred twelve billion, thirty-two million, two hundred thirteen thousand, one hundred fifty-seven".