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111112102113223 is a prime number
BaseRepresentation
bin11001010000111001001101…
…011000000110111111000111
3112120102012202102212121012111
4121100321031120012333013
5104030430041120110343
61032152110043401451
732255404320514201
oct3120711530067707
9476365672777174
10111112102113223
1132449417a57a52
121056632a223287
1349cca98414873
141d61bd6807771
15cca4328a4c9d
hex650e4d606fc7

111112102113223 has 2 divisors, whose sum is σ = 111112102113224. Its totient is φ = 111112102113222.

The previous prime is 111112102113151. The next prime is 111112102113227. The reversal of 111112102113223 is 322311201211111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111112102113223 is a prime.

It is a super-2 number, since 2×1111121021132232 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111112102113194 and 111112102113203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111112102113227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556051056611 + 55556051056612.

It is an arithmetic number, because the mean of its divisors is an integer number (55556051056612).

Almost surely, 2111112102113223 is an apocalyptic number.

111112102113223 is a deficient number, since it is larger than the sum of its proper divisors (1).

111112102113223 is an equidigital number, since it uses as much as digits as its factorization.

111112102113223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 22.

Adding to 111112102113223 its reverse (322311201211111), we get a palindrome (433423303324334).

The spelling of 111112102113223 in words is "one hundred eleven trillion, one hundred twelve billion, one hundred two million, one hundred thirteen thousand, two hundred twenty-three".