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111112130133022 = 255556065066511
BaseRepresentation
bin11001010000111001001111…
…000010111111110000011110
3112120102012211101121011010211
4121100321033002333300132
5104030430120303224042
61032152112524123034
732255405110624444
oct3120711702776036
9476365741534124
10111112130133022
1132449431855707
121056633769647a
1349ccaa1175425
141d61bda41cb94
15cca43508c017
hex650e4f0bfc1e

111112130133022 has 4 divisors (see below), whose sum is σ = 166668195199536. Its totient is φ = 55556065066510.

The previous prime is 111112130133001. The next prime is 111112130133083. The reversal of 111112130133022 is 220331031211111.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 111112130132984 and 111112130133002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27778032533254 + ... + 27778032533257.

It is an arithmetic number, because the mean of its divisors is an integer number (41667048799884).

Almost surely, 2111112130133022 is an apocalyptic number.

111112130133022 is a deficient number, since it is larger than the sum of its proper divisors (55556065066514).

111112130133022 is an equidigital number, since it uses as much as digits as its factorization.

111112130133022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55556065066513.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 111112130133022 its reverse (220331031211111), we get a palindrome (331443161344133).

The spelling of 111112130133022 in words is "one hundred eleven trillion, one hundred twelve billion, one hundred thirty million, one hundred thirty-three thousand, twenty-two".

Divisors: 1 2 55556065066511 111112130133022