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1111130258551 is a prime number
BaseRepresentation
bin10000001010110100100…
…001100011110001110111
310221020000120121111002221
4100022310201203301313
5121201043321233201
62210240213343211
7143163562235635
oct20126441436167
93836016544087
101111130258551
11399256077a85
1215b417337b07
1380a189abc91
143bac97a4355
151dd82bc04a1
hex102b4863c77

1111130258551 has 2 divisors, whose sum is σ = 1111130258552. Its totient is φ = 1111130258550.

The previous prime is 1111130258509. The next prime is 1111130258611. The reversal of 1111130258551 is 1558520311111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1111130258551 - 217 = 1111130127479 is a prime.

It is a super-2 number, since 2×11111302585512 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111134258551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555565129275 + 555565129276.

It is an arithmetic number, because the mean of its divisors is an integer number (555565129276).

Almost surely, 21111130258551 is an apocalyptic number.

1111130258551 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111130258551 is an equidigital number, since it uses as much as digits as its factorization.

1111130258551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6000, while the sum is 34.

Adding to 1111130258551 its reverse (1558520311111), we get a palindrome (2669650569662).

The spelling of 1111130258551 in words is "one trillion, one hundred eleven billion, one hundred thirty million, two hundred fifty-eight thousand, five hundred fifty-one".