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11111311003 = 13929920039
BaseRepresentation
bin10100101100100100…
…10010011010011011
31001200100220002020011
422112102102122123
5140223443423003
65034321542351
7542230404502
oct122622223233
931610802204
1011111311003
114792055461
1221a11a49b7
131080ccb650
147759a7839
1545072a46d
hex29649269b

11111311003 has 8 divisors (see below), whose sum is σ = 11978920800. Its totient is φ = 10245543168.

The previous prime is 11111310967. The next prime is 11111311007. The reversal of 11111311003 is 30011311111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11111311003 - 217 = 11111179931 is a prime.

It is a super-2 number, since 2×111113110032 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (13).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11111311007) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 447943 + ... + 472096.

It is an arithmetic number, because the mean of its divisors is an integer number (1497365100).

Almost surely, 211111311003 is an apocalyptic number.

11111311003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11111311003 is a deficient number, since it is larger than the sum of its proper divisors (867609797).

11111311003 is an equidigital number, since it uses as much as digits as its factorization.

11111311003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 920981.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 11111311003 its reverse (30011311111), we get a palindrome (41122622114).

The spelling of 11111311003 in words is "eleven billion, one hundred eleven million, three hundred eleven thousand, three".

Divisors: 1 13 929 12077 920039 11960507 854716231 11111311003