1111131126113 has 2 divisors, whose sum is σ = 1111131126114. Its totient is φ = 1111131126112.

The previous prime is 1111131126107. The next prime is 1111131126221. The reversal of 1111131126113 is 3116211311111.

It is a m-pointer prime, because the next prime (1111131126221) can be obtained adding 1111131126113 to its product of digits (108).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1106752392529 + 4378733584 = 1052023^2 + 66172^2 .

It is a cyclic number.

It is not a de Polignac number, because 1111131126113 - 2¹⁴ = 1111131109729 is a prime.

It is a super-2 number, since 2×1111131126113² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1111131126013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555565563056 + 555565563057.

It is an arithmetic number, because the mean of its divisors is an integer number (555565563057).

Almost surely, 2^{1111131126113} is an apocalyptic number.

It is an amenable number.

1111131126113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111131126113 is an equidigital number, since it uses as much as digits as its factorization.

1111131126113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 108, while the sum is 23.

Adding to 1111131126113 its reverse (3116211311111), we get a palindrome (4227342437224).

The spelling of 1111131126113 in words is "one trillion, one hundred eleven billion, one hundred thirty-one million, one hundred twenty-six thousand, one hundred thirteen".