111113131 has 2 divisors, whose sum is σ = 111113132. Its totient is φ = 111113130.

The previous prime is 111113113. The next prime is 111113137. The reversal of 111113131 is 131311111.

Together with previous prime (111113113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111113131 - 2⁵ = 111113099 is a prime.

It is a super-2 number, since 2×111113131² = 24692255761246322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (111113137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556565 + 55556566.

It is an arithmetic number, because the mean of its divisors is an integer number (55556566).

Almost surely, 2^111113131 is an apocalyptic number.

111113131 is a deficient number, since it is larger than the sum of its proper divisors (1).

111113131 is an equidigital number, since it uses as much as digits as its factorization.

111113131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9, while the sum is 13.

The square root of 111113131 is about 10541.0213452018. The cubic root of 111113131 is about 480.7527699354.

Adding to 111113131 its reverse (131311111), we get a palindrome (242424242).

It can be divided in two parts, 1111 and 13131, that multiplied together give a palindrome (14588541).

The spelling of 111113131 in words is "one hundred eleven million, one hundred thirteen thousand, one hundred thirty-one".